Comments on: Snippet: Creating & Debugging Complex SQL queries in Symfony

By: ErisDS

ErisDS — Thu, 26 Aug 2010 15:20:03 +0000

Well that still doesn’t have a comma between your SELECT items, and the quotes are all different – look at the ones around “select” and then look at the other ones… they are not the same.

By: benbrahim

benbrahim — Thu, 26 Aug 2010 15:15:38 +0000

thanks you, i fund the mistak i’m added \” in like condition
$sql = ‘select ‘. self::NAME .” “. self::LASTNAME.” from ” .self::TABLE_NAME .” where “.self::NAME .” like \”%a%\” ” ;

By: ErisDS

ErisDS — Thu, 26 Aug 2010 12:42:57 +0000

Try copying my code snippet from my earlier comment where I have matched all the quotes properly – yours are all mixed up. Also you are missing the comma between your select fields.

Try

1	print_r($sql);

as well – that should help show you where the mistakes are.

By: benbrahim

benbrahim — Wed, 25 Aug 2010 11:58:35 +0000

i’am using propel but i wish using this type of query $sql = ‘select ‘. self::NAME .” “. self::LASTNAME.” from ” .self::TABLE_NAME .” where “.self::NAME .” like .‘%a%’ ” ;

By: ErisDS

ErisDS — Tue, 24 Aug 2010 15:01:36 +0000

At first glance, the only problem I can see is that your quotes are all mixed up.

You need to pay special attention to these, use spacing properly to make it easier to read and you will spot those mistakes more easily:

1	$sql = 'SELECT ' . self::NAME . ', ' . self::LASTNAME . ' FROM ' . self::TABLE_NAME . ' WHERE ' . self::NAME . ' LIKE "%a%"' ;

Not sure if you’re using doctrine or propel as you didn’t say, but with Propel Criteria there is no reason why you would need to use SQL to create this query. Instead use:

1	$criteria->add(self::NAME, "%a%", Criteria::LIKE);

By: benbrahim

benbrahim — Tue, 24 Aug 2010 14:52:40 +0000

thanks for your post, i wish to add a like, to produce this sql like this : select branch.ROOT_ID, branch.NAME FROM `branch` WHERE branch.NAME like ‘%all%’ ;
any idea ?!!!
this is my code
$sql = ‘select ‘. self::NAME .” “. self::LASTNAME.” from ” .self::TABLE_NAME .” where “.self::NAME .” like ‘%a%’ ” ;
but i have error in ‘%a%’ do you now why !!!!
thanks